41100114113 has 4 divisors (see below), whose sum is σ = 41713548720. Its totient is φ = 40486679508.

The previous prime is 41100114091. The next prime is 41100114161. The reversal of 41100114113 is 31141100114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31141100114 = 2 ⋅15570550057.

It is a cyclic number.

It is not a de Polignac number, because 41100114113 - 2¹⁴ = 41100097729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41100114091 and 41100114100.

It is not an unprimeable number, because it can be changed into a prime (41100164113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306717203 + ... + 306717336.

It is an arithmetic number, because the mean of its divisors is an integer number (10428387180).

Almost surely, 2^41100114113 is an apocalyptic number.

It is an amenable number.

41100114113 is a deficient number, since it is larger than the sum of its proper divisors (613434607).

41100114113 is an equidigital number, since it uses as much as digits as its factorization.

41100114113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 613434606.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 41100114113 its reverse (31141100114), we get a palindrome (72241214227).

The spelling of 41100114113 in words is "forty-one billion, one hundred million, one hundred fourteen thousand, one hundred thirteen".