Base | Representation |
---|---|
bin | 100110010001110000… |
… | …100001101101111011 |
3 | 10221002100010120112220 |
4 | 212101300201231323 |
5 | 1133133112414003 |
6 | 30514154135123 |
7 | 2653333165332 |
oct | 462160415573 |
9 | 127070116486 |
10 | 41100123003 |
11 | 16480a47805 |
12 | 7b704214a3 |
13 | 3b4cc77214 |
14 | 1dbc73cd19 |
15 | 1108394353 |
hex | 991c21b7b |
41100123003 has 4 divisors (see below), whose sum is σ = 54800164008. Its totient is φ = 27400082000.
The previous prime is 41100122983. The next prime is 41100123059. The reversal of 41100123003 is 30032100114.
41100123003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41100123003 - 25 = 41100122971 is a prime.
It is a super-2 number, since 2×411001230032 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (41100124003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6850020498 + ... + 6850020503.
It is an arithmetic number, because the mean of its divisors is an integer number (13700041002).
Almost surely, 241100123003 is an apocalyptic number.
41100123003 is a deficient number, since it is larger than the sum of its proper divisors (13700041005).
41100123003 is a wasteful number, since it uses less digits than its factorization.
41100123003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13700041004.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 41100123003 its reverse (30032100114), we get a palindrome (71132223117).
The spelling of 41100123003 in words is "forty-one billion, one hundred million, one hundred twenty-three thousand, three".
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