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4110132001 is a prime number
BaseRepresentation
bin1111010011111011…
…1010001100100001
3101121102221100011011
43310332322030201
531404143211001
61515502220521
7203565355063
oct36476721441
911542840134
104110132001
11181a076008
12968584741
135066a1b91
142adc21733
15190c7bd51
hexf4fba321

4110132001 has 2 divisors, whose sum is σ = 4110132002. Its totient is φ = 4110132000.

The previous prime is 4110131989. The next prime is 4110132107. The reversal of 4110132001 is 1002310114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2412774400 + 1697357601 = 49120^2 + 41199^2 .

It is a cyclic number.

It is not a de Polignac number, because 4110132001 - 29 = 4110131489 is a prime.

It is not a weakly prime, because it can be changed into another prime (4110132701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055066000 + 2055066001.

It is an arithmetic number, because the mean of its divisors is an integer number (2055066001).

Almost surely, 24110132001 is an apocalyptic number.

It is an amenable number.

4110132001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4110132001 is an equidigital number, since it uses as much as digits as its factorization.

4110132001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 4110132001 is about 64110.3111909465. The cubic root of 4110132001 is about 1601.8379921040.

Adding to 4110132001 its reverse (1002310114), we get a palindrome (5112442115).

The spelling of 4110132001 in words is "four billion, one hundred ten million, one hundred thirty-two thousand, one".