Base | Representation |
---|---|
bin | 100110010001110101… |
… | …010000111110001101 |
3 | 10221002102110200102201 |
4 | 212101311100332031 |
5 | 1133133422141013 |
6 | 30514240521501 |
7 | 2653346560603 |
oct | 462165207615 |
9 | 127072420381 |
10 | 41101365133 |
11 | 16481715a64 |
12 | 7b70920291 |
13 | 3b502c06ca |
14 | 1dbc983873 |
15 | 110853c3dd |
hex | 991d50f8d |
41101365133 has 2 divisors, whose sum is σ = 41101365134. Its totient is φ = 41101365132.
The previous prime is 41101365101. The next prime is 41101365167. The reversal of 41101365133 is 33156310114.
41101365133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40335902244 + 765462889 = 200838^2 + 27667^2 .
It is a cyclic number.
It is not a de Polignac number, because 41101365133 - 25 = 41101365101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41101365733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550682566 + 20550682567.
It is an arithmetic number, because the mean of its divisors is an integer number (20550682567).
Almost surely, 241101365133 is an apocalyptic number.
It is an amenable number.
41101365133 is a deficient number, since it is larger than the sum of its proper divisors (1).
41101365133 is an equidigital number, since it uses as much as digits as its factorization.
41101365133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 28.
Adding to 41101365133 its reverse (33156310114), we get a palindrome (74257675247).
The spelling of 41101365133 in words is "forty-one billion, one hundred one million, three hundred sixty-five thousand, one hundred thirty-three".
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