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411020132153 is a prime number
BaseRepresentation
bin1011111101100101011…
…01010111111100111001
31110021220200220002100112
411332302231113330321
523213232123212103
6512453043514105
741460314323121
oct5766255277471
91407820802315
10411020132153
11149349170834
12677a9988935
132c9b37942b7
1415c719d3c81
15aa59112cd8
hex5fb2b57f39

411020132153 has 2 divisors, whose sum is σ = 411020132154. Its totient is φ = 411020132152.

The previous prime is 411020132147. The next prime is 411020132249. The reversal of 411020132153 is 351231020114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 357062417209 + 53957714944 = 597547^2 + 232288^2 .

It is a cyclic number.

It is not a de Polignac number, because 411020132153 - 228 = 410751696697 is a prime.

It is not a weakly prime, because it can be changed into another prime (411020132123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205510066076 + 205510066077.

It is an arithmetic number, because the mean of its divisors is an integer number (205510066077).

Almost surely, 2411020132153 is an apocalyptic number.

It is an amenable number.

411020132153 is a deficient number, since it is larger than the sum of its proper divisors (1).

411020132153 is an equidigital number, since it uses as much as digits as its factorization.

411020132153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 411020132153 its reverse (351231020114), we get a palindrome (762251152267).

The spelling of 411020132153 in words is "four hundred eleven billion, twenty million, one hundred thirty-two thousand, one hundred fifty-three".