Base | Representation |
---|---|
bin | 1011111101100101011… |
… | …01010111111100111001 |
3 | 1110021220200220002100112 |
4 | 11332302231113330321 |
5 | 23213232123212103 |
6 | 512453043514105 |
7 | 41460314323121 |
oct | 5766255277471 |
9 | 1407820802315 |
10 | 411020132153 |
11 | 149349170834 |
12 | 677a9988935 |
13 | 2c9b37942b7 |
14 | 15c719d3c81 |
15 | aa59112cd8 |
hex | 5fb2b57f39 |
411020132153 has 2 divisors, whose sum is σ = 411020132154. Its totient is φ = 411020132152.
The previous prime is 411020132147. The next prime is 411020132249. The reversal of 411020132153 is 351231020114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 357062417209 + 53957714944 = 597547^2 + 232288^2 .
It is a cyclic number.
It is not a de Polignac number, because 411020132153 - 228 = 410751696697 is a prime.
It is not a weakly prime, because it can be changed into another prime (411020132123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205510066076 + 205510066077.
It is an arithmetic number, because the mean of its divisors is an integer number (205510066077).
Almost surely, 2411020132153 is an apocalyptic number.
It is an amenable number.
411020132153 is a deficient number, since it is larger than the sum of its proper divisors (1).
411020132153 is an equidigital number, since it uses as much as digits as its factorization.
411020132153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 411020132153 its reverse (351231020114), we get a palindrome (762251152267).
The spelling of 411020132153 in words is "four hundred eleven billion, twenty million, one hundred thirty-two thousand, one hundred fifty-three".
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