Base | Representation |
---|---|
bin | 100110010001111001… |
… | …010101110001011011 |
3 | 10221002111110221210002 |
4 | 212101321111301123 |
5 | 1133134210331441 |
6 | 30514315443215 |
7 | 2653361630156 |
oct | 462171256133 |
9 | 127074427702 |
10 | 41102433371 |
11 | 164822855aa |
12 | 7b7115650b |
13 | 3b505a59bc |
14 | 1dbcb80c9d |
15 | 110869db9b |
hex | 991e55c5b |
41102433371 has 2 divisors, whose sum is σ = 41102433372. Its totient is φ = 41102433370.
The previous prime is 41102433331. The next prime is 41102433377. The reversal of 41102433371 is 17333420114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41102433371 - 222 = 41098239067 is a prime.
It is not a weakly prime, because it can be changed into another prime (41102433377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20551216685 + 20551216686.
It is an arithmetic number, because the mean of its divisors is an integer number (20551216686).
Almost surely, 241102433371 is an apocalyptic number.
41102433371 is a deficient number, since it is larger than the sum of its proper divisors (1).
41102433371 is an equidigital number, since it uses as much as digits as its factorization.
41102433371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 41102433371 its reverse (17333420114), we get a palindrome (58435853485).
The spelling of 41102433371 in words is "forty-one billion, one hundred two million, four hundred thirty-three thousand, three hundred seventy-one".
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