Base | Representation |
---|---|
bin | 100110010001111001… |
… | …010101110000110011 |
3 | 10221002111110221201121 |
4 | 212101321111300303 |
5 | 1133134210331311 |
6 | 30514315443111 |
7 | 2653361630101 |
oct | 462171256063 |
9 | 127074427647 |
10 | 41102433331 |
11 | 16482285573 |
12 | 7b71156497 |
13 | 3b505a598b |
14 | 1dbcb80c71 |
15 | 110869db71 |
hex | 991e55c33 |
41102433331 has 2 divisors, whose sum is σ = 41102433332. Its totient is φ = 41102433330.
The previous prime is 41102433329. The next prime is 41102433371. The reversal of 41102433331 is 13333420114.
41102433331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41102433331 - 21 = 41102433329 is a prime.
It is a super-2 number, since 2×411024333312 (a number of 22 digits) contains 22 as substring.
Together with 41102433329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 41102433296 and 41102433305.
It is not a weakly prime, because it can be changed into another prime (41102433371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20551216665 + 20551216666.
It is an arithmetic number, because the mean of its divisors is an integer number (20551216666).
Almost surely, 241102433331 is an apocalyptic number.
41102433331 is a deficient number, since it is larger than the sum of its proper divisors (1).
41102433331 is an equidigital number, since it uses as much as digits as its factorization.
41102433331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 41102433331 its reverse (13333420114), we get a palindrome (54435853445).
The spelling of 41102433331 in words is "forty-one billion, one hundred two million, four hundred thirty-three thousand, three hundred thirty-one".
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