411025514113 has 2 divisors, whose sum is σ = 411025514114. Its totient is φ = 411025514112.

The previous prime is 411025514071. The next prime is 411025514129. The reversal of 411025514113 is 311415520114.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 401895138304 + 9130375809 = 633952^2 + 95553^2 .

It is a cyclic number.

It is not a de Polignac number, because 411025514113 - 2³⁷ = 273586560641 is a prime.

It is a super-3 number, since 3×411025514113³ (a number of 36 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (411025514183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205512757056 + 205512757057.

It is an arithmetic number, because the mean of its divisors is an integer number (205512757057).

Almost surely, 2^411025514113 is an apocalyptic number.

It is an amenable number.

411025514113 is a deficient number, since it is larger than the sum of its proper divisors (1).

411025514113 is an equidigital number, since it uses as much as digits as its factorization.

411025514113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 28.

The spelling of 411025514113 in words is "four hundred eleven billion, twenty-five million, five hundred fourteen thousand, one hundred thirteen".