41104121 has 2 divisors, whose sum is σ = 41104122. Its totient is φ = 41104120.

The previous prime is 41104117. The next prime is 41104123. The reversal of 41104121 is 12140114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36421225 + 4682896 = 6035^2 + 2164^2 .

It is a cyclic number.

It is not a de Polignac number, because 41104121 - 2² = 41104117 is a prime.

Together with 41104123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 41104096 and 41104105.

It is not a weakly prime, because it can be changed into another prime (41104123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20552060 + 20552061.

It is an arithmetic number, because the mean of its divisors is an integer number (20552061).

Almost surely, 2^41104121 is an apocalyptic number.

It is an amenable number.

41104121 is a deficient number, since it is larger than the sum of its proper divisors (1).

41104121 is an equidigital number, since it uses as much as digits as its factorization.

41104121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

The square root of 41104121 is about 6411.2495661922. The cubic root of 41104121 is about 345.1133730875.

Adding to 41104121 its reverse (12140114), we get a palindrome (53244235).

The spelling of 41104121 in words is "forty-one million, one hundred four thousand, one hundred twenty-one".