411043323211132 has 12 divisors (see below), whose sum is σ = 720136780468560. Its totient is φ = 205289957362976.

The previous prime is 411043323211061. The next prime is 411043323211177. The reversal of 411043323211132 is 231112323340114.

It is a super-2 number, since 2×411043323211132² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 411043323211094 and 411043323211103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57926056657 + ... + 57926063752.

It is an arithmetic number, because the mean of its divisors is an integer number (60011398372380).

Almost surely, 2^{411043323211132} is an apocalyptic number.

It is an amenable number.

411043323211132 is a deficient number, since it is larger than the sum of its proper divisors (309093457257428).

411043323211132 is a wasteful number, since it uses less digits than its factorization.

411043323211132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115852121300 (or 115852121298 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 411043323211132 its reverse (231112323340114), we get a palindrome (642155646551246).

The spelling of 411043323211132 in words is "four hundred eleven trillion, forty-three billion, three hundred twenty-three million, two hundred eleven thousand, one hundred thirty-two".