Base | Representation |
---|---|
bin | 1011111101101001011… |
… | …11011000000001001111 |
3 | 1110022000002000110221122 |
4 | 11332310233120001033 |
5 | 23213314334224101 |
6 | 512500302151155 |
7 | 41461210100603 |
oct | 5766457300117 |
9 | 1408002013848 |
10 | 411054211151 |
11 | 1493664278a1 |
12 | 677b92824bb |
13 | 2c9ba866a9c |
14 | 15c76345503 |
15 | aa5c0e551b |
hex | 5fb4bd804f |
411054211151 has 2 divisors, whose sum is σ = 411054211152. Its totient is φ = 411054211150.
The previous prime is 411054211103. The next prime is 411054211157. The reversal of 411054211151 is 151112450114.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-411054211151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 411054211151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411054211157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205527105575 + 205527105576.
It is an arithmetic number, because the mean of its divisors is an integer number (205527105576).
Almost surely, 2411054211151 is an apocalyptic number.
411054211151 is a deficient number, since it is larger than the sum of its proper divisors (1).
411054211151 is an equidigital number, since it uses as much as digits as its factorization.
411054211151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 800, while the sum is 26.
Adding to 411054211151 its reverse (151112450114), we get a palindrome (562166661265).
The spelling of 411054211151 in words is "four hundred eleven billion, fifty-four million, two hundred eleven thousand, one hundred fifty-one".
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