4111012140121 has 2 divisors, whose sum is σ = 4111012140122. Its totient is φ = 4111012140120.

The previous prime is 4111012140097. The next prime is 4111012140143. The reversal of 4111012140121 is 1210412101114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3426811857225 + 684200282896 = 1851165^2 + 827164^2 .

It is a cyclic number.

It is not a de Polignac number, because 4111012140121 - 2¹³ = 4111012131929 is a prime.

It is not a weakly prime, because it can be changed into another prime (4111712140121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055506070060 + 2055506070061.

It is an arithmetic number, because the mean of its divisors is an integer number (2055506070061).

Almost surely, 2^{4111012140121} is an apocalyptic number.

It is an amenable number.

4111012140121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111012140121 is an equidigital number, since it uses as much as digits as its factorization.

4111012140121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 4111012140121 its reverse (1210412101114), we get a palindrome (5321424241235).

The spelling of 4111012140121 in words is "four trillion, one hundred eleven billion, twelve million, one hundred forty thousand, one hundred twenty-one".