41110400132401 has 2 divisors, whose sum is σ = 41110400132402. Its totient is φ = 41110400132400.

The previous prime is 41110400132369. The next prime is 41110400132447. The reversal of 41110400132401 is 10423100401114.

41110400132401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24823113998400 + 16287286134001 = 4982280^2 + 4035751^2 .

It is a cyclic number.

It is not a de Polignac number, because 41110400132401 - 2⁵ = 41110400132369 is a prime.

It is a super-4 number, since 4×41110400132401⁴ (a number of 56 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (41110400162401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20555200066200 + 20555200066201.

It is an arithmetic number, because the mean of its divisors is an integer number (20555200066201).

Almost surely, 2^{41110400132401} is an apocalyptic number.

It is an amenable number.

41110400132401 is a deficient number, since it is larger than the sum of its proper divisors (1).

41110400132401 is an equidigital number, since it uses as much as digits as its factorization.

41110400132401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 41110400132401 its reverse (10423100401114), we get a palindrome (51533500533515).

The spelling of 41110400132401 in words is "forty-one trillion, one hundred ten billion, four hundred million, one hundred thirty-two thousand, four hundred one".