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4111114853 is a prime number
BaseRepresentation
bin1111010100001010…
…1010001001100101
3101121111210021101002
43311002222021211
531404421133403
61515535243045
7203606620406
oct36502521145
911544707332
104111114853
11181a68748a
12968979485
13506957351
142addd99ad
15190dc3188
hexf50aa265

4111114853 has 2 divisors, whose sum is σ = 4111114854. Its totient is φ = 4111114852.

The previous prime is 4111114837. The next prime is 4111114883. The reversal of 4111114853 is 3584111114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2985311044 + 1125803809 = 54638^2 + 33553^2 .

It is a cyclic number.

It is not a de Polignac number, because 4111114853 - 24 = 4111114837 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4111114823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055557426 + 2055557427.

It is an arithmetic number, because the mean of its divisors is an integer number (2055557427).

Almost surely, 24111114853 is an apocalyptic number.

It is an amenable number.

4111114853 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111114853 is an equidigital number, since it uses as much as digits as its factorization.

4111114853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1920, while the sum is 29.

The square root of 4111114853 is about 64117.9760519622. The cubic root of 4111114853 is about 1601.9656639321.

Adding to 4111114853 its reverse (3584111114), we get a palindrome (7695225967).

The spelling of 4111114853 in words is "four billion, one hundred eleven million, one hundred fourteen thousand, eight hundred fifty-three".