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4111212311111 is a prime number
BaseRepresentation
bin111011110100110111010…
…110010111001001000111
3112120000202110021110111202
4323310313112113021013
51014324230322423421
612424355335453115
7603011450025233
oct73646726271107
915500673243452
104111212311111
111345612196a94
1256494482719b
1323a8bb50a599
14102dab5395c3
1571e1e72110b
hex3bd37597247

4111212311111 has 2 divisors, whose sum is σ = 4111212311112. Its totient is φ = 4111212311110.

The previous prime is 4111212311051. The next prime is 4111212311159. The reversal of 4111212311111 is 1111132121114.

It is a m-pointer prime, because the next prime (4111212311159) can be obtained adding 4111212311111 to its product of digits (48).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4111212311111 - 226 = 4111145202247 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4111212311161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055606155555 + 2055606155556.

It is an arithmetic number, because the mean of its divisors is an integer number (2055606155556).

Almost surely, 24111212311111 is an apocalyptic number.

4111212311111 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111212311111 is an equidigital number, since it uses as much as digits as its factorization.

4111212311111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 20.

Adding to 4111212311111 its reverse (1111132121114), we get a palindrome (5222344432225).

The spelling of 4111212311111 in words is "four trillion, one hundred eleven billion, two hundred twelve million, three hundred eleven thousand, one hundred eleven".