41113030441141 has 4 divisors (see below), whose sum is σ = 41221508094400. Its totient is φ = 41004552787884.

The previous prime is 41113030441127. The next prime is 41113030441159. The reversal of 41113030441141 is 14114403031114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41113030441141 - 2¹⁷ = 41113030310069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41113030441121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54238826061 + ... + 54238826818.

It is an arithmetic number, because the mean of its divisors is an integer number (10305377023600).

Almost surely, 2^{41113030441141} is an apocalyptic number.

It is an amenable number.

41113030441141 is a deficient number, since it is larger than the sum of its proper divisors (108477653259).

41113030441141 is a wasteful number, since it uses less digits than its factorization.

41113030441141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108477653258.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 41113030441141 its reverse (14114403031114), we get a palindrome (55227433472255).

The spelling of 41113030441141 in words is "forty-one trillion, one hundred thirteen billion, thirty million, four hundred forty-one thousand, one hundred forty-one".