Base | Representation |
---|---|
bin | 100110010010100010… |
… | …000010000010000011 |
3 | 10221010020112220012221 |
4 | 212102202002002003 |
5 | 1133144423203134 |
6 | 30515340231511 |
7 | 2653551405346 |
oct | 462242020203 |
9 | 127106486187 |
10 | 41113100419 |
11 | 16488300946 |
12 | 7b7483b597 |
13 | 3b5286c071 |
14 | 1dc035a45d |
15 | 11095a95b4 |
hex | 992882083 |
41113100419 has 2 divisors, whose sum is σ = 41113100420. Its totient is φ = 41113100418.
The previous prime is 41113100293. The next prime is 41113100437. The reversal of 41113100419 is 91400131114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41113100419 - 227 = 40978882691 is a prime.
It is a super-2 number, since 2×411131004192 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41113100393 and 41113100402.
It is not a weakly prime, because it can be changed into another prime (41113100719) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556550209 + 20556550210.
It is an arithmetic number, because the mean of its divisors is an integer number (20556550210).
Almost surely, 241113100419 is an apocalyptic number.
41113100419 is a deficient number, since it is larger than the sum of its proper divisors (1).
41113100419 is an equidigital number, since it uses as much as digits as its factorization.
41113100419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 41113100419 in words is "forty-one billion, one hundred thirteen million, one hundred thousand, four hundred nineteen".
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