41113113434333 has 4 divisors (see below), whose sum is σ = 41113158395100. Its totient is φ = 41113068473568.

The previous prime is 41113113434317. The next prime is 41113113434339. The reversal of 41113113434333 is 33343431131114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17281796351044 + 23831317083289 = 4157138^2 + 4881733^2 .

It is a cyclic number.

It is not a de Polignac number, because 41113113434333 - 2⁴ = 41113113434317 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41113113434293 and 41113113434302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41113113434339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21079658 + ... + 22947291.

It is an arithmetic number, because the mean of its divisors is an integer number (10278289598775).

Almost surely, 2^{41113113434333} is an apocalyptic number.

It is an amenable number.

41113113434333 is a deficient number, since it is larger than the sum of its proper divisors (44960767).

41113113434333 is an equidigital number, since it uses as much as digits as its factorization.

41113113434333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44960766.

The product of its digits is 46656, while the sum is 35.

Adding to 41113113434333 its reverse (33343431131114), we get a palindrome (74456544565447).

The spelling of 41113113434333 in words is "forty-one trillion, one hundred thirteen billion, one hundred thirteen million, four hundred thirty-four thousand, three hundred thirty-three".