4111311421111 has 2 divisors, whose sum is σ = 4111311421112. Its totient is φ = 4111311421110.

The previous prime is 4111311421051. The next prime is 4111311421207. The reversal of 4111311421111 is 1111241131114.

It is a m-pointer prime, because the next prime (4111311421207) can be obtained adding 4111311421111 to its product of digits (96).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4111311421111 - 2¹⁷ = 4111311290039 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4111311451111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055655710555 + 2055655710556.

It is an arithmetic number, because the mean of its divisors is an integer number (2055655710556).

Almost surely, 2^{4111311421111} is an apocalyptic number.

4111311421111 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111311421111 is an equidigital number, since it uses as much as digits as its factorization.

4111311421111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96, while the sum is 22.

Adding to 4111311421111 its reverse (1111241131114), we get a palindrome (5222552552225).

The spelling of 4111311421111 in words is "four trillion, one hundred eleven billion, three hundred eleven million, four hundred twenty-one thousand, one hundred eleven".