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41113141141 is a prime number
BaseRepresentation
bin100110010010100010…
…001011111110010101
310221010020121222002011
4212102202023332111
51133144431004031
630515341144221
72653551635152
oct462242137625
9127106558064
1041113141141
11164883294a6
127b7485b071
133b52884767
141dc036b229
1511095b66b1
hex99288bf95

41113141141 has 2 divisors, whose sum is σ = 41113141142. Its totient is φ = 41113141140.

The previous prime is 41113141117. The next prime is 41113141151. The reversal of 41113141141 is 14114131114.

41113141141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23602176900 + 17510964241 = 153630^2 + 132329^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41113141141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41113141151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556570570 + 20556570571.

It is an arithmetic number, because the mean of its divisors is an integer number (20556570571).

Almost surely, 241113141141 is an apocalyptic number.

It is an amenable number.

41113141141 is a deficient number, since it is larger than the sum of its proper divisors (1).

41113141141 is an equidigital number, since it uses as much as digits as its factorization.

41113141141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 192, while the sum is 22.

Adding to 41113141141 its reverse (14114131114), we get a palindrome (55227272255).

The spelling of 41113141141 in words is "forty-one billion, one hundred thirteen million, one hundred forty-one thousand, one hundred forty-one".