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4111393490471 is a prime number
BaseRepresentation
bin111011110101000010001…
…001100000011000100111
3112120001020002012022212102
4323311002021200120213
51014330113213143341
612424425331042315
7603016110025031
oct73650211403047
915501202168772
104111393490471
1113456a54947a3
1256499544039b
1323a919c051c7
14102dc761cc51
1571e305adc9b
hex3bd42260627

4111393490471 has 2 divisors, whose sum is σ = 4111393490472. Its totient is φ = 4111393490470.

The previous prime is 4111393490447. The next prime is 4111393490513. The reversal of 4111393490471 is 1740943931114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4111393490471 - 214 = 4111393474087 is a prime.

It is a super-3 number, since 3×41113934904713 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4110393490471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055696745235 + 2055696745236.

It is an arithmetic number, because the mean of its divisors is an integer number (2055696745236).

Almost surely, 24111393490471 is an apocalyptic number.

4111393490471 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111393490471 is an equidigital number, since it uses as much as digits as its factorization.

4111393490471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 47.

The spelling of 4111393490471 in words is "four trillion, one hundred eleven billion, three hundred ninety-three million, four hundred ninety thousand, four hundred seventy-one".