Base | Representation |
---|---|
bin | 111011110101000010001… |
… | …001100000011000100111 |
3 | 112120001020002012022212102 |
4 | 323311002021200120213 |
5 | 1014330113213143341 |
6 | 12424425331042315 |
7 | 603016110025031 |
oct | 73650211403047 |
9 | 15501202168772 |
10 | 4111393490471 |
11 | 13456a54947a3 |
12 | 56499544039b |
13 | 23a919c051c7 |
14 | 102dc761cc51 |
15 | 71e305adc9b |
hex | 3bd42260627 |
4111393490471 has 2 divisors, whose sum is σ = 4111393490472. Its totient is φ = 4111393490470.
The previous prime is 4111393490447. The next prime is 4111393490513. The reversal of 4111393490471 is 1740943931114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4111393490471 - 214 = 4111393474087 is a prime.
It is a super-3 number, since 3×41113934904713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4110393490471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055696745235 + 2055696745236.
It is an arithmetic number, because the mean of its divisors is an integer number (2055696745236).
Almost surely, 24111393490471 is an apocalyptic number.
4111393490471 is a deficient number, since it is larger than the sum of its proper divisors (1).
4111393490471 is an equidigital number, since it uses as much as digits as its factorization.
4111393490471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 326592, while the sum is 47.
The spelling of 4111393490471 in words is "four trillion, one hundred eleven billion, three hundred ninety-three million, four hundred ninety thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •