411141031001301 has 4 divisors (see below), whose sum is σ = 548188041335072. Its totient is φ = 274094020667532.

The previous prime is 411141031001297. The next prime is 411141031001333. The reversal of 411141031001301 is 103100130141114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 411141031001301 - 2² = 411141031001297 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411141031001801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68523505166881 + ... + 68523505166886.

It is an arithmetic number, because the mean of its divisors is an integer number (137047010333768).

Almost surely, 2^{411141031001301} is an apocalyptic number.

It is an amenable number.

411141031001301 is a deficient number, since it is larger than the sum of its proper divisors (137047010333771).

411141031001301 is a wasteful number, since it uses less digits than its factorization.

411141031001301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137047010333770.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 411141031001301 its reverse (103100130141114), we get a palindrome (514241161142415).

The spelling of 411141031001301 in words is "four hundred eleven trillion, one hundred forty-one billion, thirty-one million, one thousand, three hundred one".