4111414081 has 2 divisors, whose sum is σ = 4111414082. Its totient is φ = 4111414080.

The previous prime is 4111414033. The next prime is 4111414121. The reversal of 4111414081 is 1804141114.

4111414081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3296597056 + 814817025 = 57416^2 + 28545^2 .

It is a cyclic number.

It is not a de Polignac number, because 4111414081 - 2²¹ = 4109316929 is a prime.

It is a super-2 number, since 2×4111414081² = 33807451490890149122, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4111414001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055707040 + 2055707041.

It is an arithmetic number, because the mean of its divisors is an integer number (2055707041).

Almost surely, 2^4111414081 is an apocalyptic number.

It is an amenable number.

4111414081 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111414081 is an equidigital number, since it uses as much as digits as its factorization.

4111414081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 512, while the sum is 25.

The square root of 4111414081 is about 64120.3094268891. The cubic root of 4111414081 is about 1602.0045294118.

Adding to 4111414081 its reverse (1804141114), we get a palindrome (5915555195).

The spelling of 4111414081 in words is "four billion, one hundred eleven million, four hundred fourteen thousand, eighty-one".