4111414121 has 2 divisors, whose sum is σ = 4111414122. Its totient is φ = 4111414120.

The previous prime is 4111414081. The next prime is 4111414133. The reversal of 4111414121 is 1214141114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3483360400 + 628053721 = 59020^2 + 25061^2 .

It is a cyclic number.

It is not a de Polignac number, because 4111414121 - 2¹⁸ = 4111151977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4111414093 and 4111414102.

It is not a weakly prime, because it can be changed into another prime (4111419121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055707060 + 2055707061.

It is an arithmetic number, because the mean of its divisors is an integer number (2055707061).

Almost surely, 2^4111414121 is an apocalyptic number.

It is an amenable number.

4111414121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111414121 is an equidigital number, since it uses as much as digits as its factorization.

4111414121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 128, while the sum is 20.

The square root of 4111414121 is about 64120.3097388027. The cubic root of 4111414121 is about 1602.0045346071.

Adding to 4111414121 its reverse (1214141114), we get a palindrome (5325555235).

The spelling of 4111414121 in words is "four billion, one hundred eleven million, four hundred fourteen thousand, one hundred twenty-one".