Base | Representation |
---|---|
bin | 1011111101110100000… |
… | …11010011101000010101 |
3 | 1110022020021200210020101 |
4 | 11332322003103220111 |
5 | 23214010142302013 |
6 | 512513204134101 |
7 | 41463341401435 |
oct | 5767203235025 |
9 | 1408207623211 |
10 | 411143322133 |
11 | 149401761235 |
12 | 67823097331 |
13 | 2ca0316718b |
14 | 15c841002c5 |
15 | aa64d488dd |
hex | 5fba0d3a15 |
411143322133 has 2 divisors, whose sum is σ = 411143322134. Its totient is φ = 411143322132.
The previous prime is 411143322113. The next prime is 411143322137. The reversal of 411143322133 is 331223341114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 217549482084 + 193593840049 = 466422^2 + 439993^2 .
It is a cyclic number.
It is not a de Polignac number, because 411143322133 - 29 = 411143321621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411143322137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205571661066 + 205571661067.
It is an arithmetic number, because the mean of its divisors is an integer number (205571661067).
Almost surely, 2411143322133 is an apocalyptic number.
It is an amenable number.
411143322133 is a deficient number, since it is larger than the sum of its proper divisors (1).
411143322133 is an equidigital number, since it uses as much as digits as its factorization.
411143322133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 28.
Adding to 411143322133 its reverse (331223341114), we get a palindrome (742366663247).
The spelling of 411143322133 in words is "four hundred eleven billion, one hundred forty-three million, three hundred twenty-two thousand, one hundred thirty-three".
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