Base | Representation |
---|---|
bin | 1111010100010000… |
… | …1101000111001001 |
3 | 101121112112212101222 |
4 | 3311010031013021 |
5 | 31410022121301 |
6 | 1515552051425 |
7 | 203613226235 |
oct | 36504150711 |
9 | 11545485358 |
10 | 4111520201 |
11 | 181a933a88 |
12 | 968b33b75 |
13 | 506a699b9 |
14 | 2b00a35c5 |
15 | 190e5331b |
hex | f510d1c9 |
4111520201 has 2 divisors, whose sum is σ = 4111520202. Its totient is φ = 4111520200.
The previous prime is 4111520183. The next prime is 4111520213. The reversal of 4111520201 is 1020251114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2180796601 + 1930723600 = 46699^2 + 43940^2 .
It is a cyclic number.
It is not a de Polignac number, because 4111520201 - 26 = 4111520137 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4111520201.
It is not a weakly prime, because it can be changed into another prime (4111520701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055760100 + 2055760101.
It is an arithmetic number, because the mean of its divisors is an integer number (2055760101).
Almost surely, 24111520201 is an apocalyptic number.
It is an amenable number.
4111520201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4111520201 is an equidigital number, since it uses as much as digits as its factorization.
4111520201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
The square root of 4111520201 is about 64121.1369284731. The cubic root of 4111520201 is about 1602.0183124440.
Adding to 4111520201 its reverse (1020251114), we get a palindrome (5131771315).
It can be divided in two parts, 41115 and 20201, that added together give a palindrome (61316).
The spelling of 4111520201 in words is "four billion, one hundred eleven million, five hundred twenty thousand, two hundred one".
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