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4111539561013 is a prime number
BaseRepresentation
bin111011110101001010110…
…110101110001000110101
3112120001121021001110222111
4323311022312232020311
51014330413111423023
612424452025531021
7603022532430463
oct73651266561065
915501537043874
104111539561013
11134576a992755
12564a16343a71
1323a941259691
14102ddcba3833
1571e3d31400d
hex3bd4adae235

4111539561013 has 2 divisors, whose sum is σ = 4111539561014. Its totient is φ = 4111539561012.

The previous prime is 4111539560959. The next prime is 4111539561023. The reversal of 4111539561013 is 3101659351114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4056868703889 + 54670857124 = 2014167^2 + 233818^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4111539561013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4111539561023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055769780506 + 2055769780507.

It is an arithmetic number, because the mean of its divisors is an integer number (2055769780507).

Almost surely, 24111539561013 is an apocalyptic number.

It is an amenable number.

4111539561013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111539561013 is an equidigital number, since it uses as much as digits as its factorization.

4111539561013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 40.

The spelling of 4111539561013 in words is "four trillion, one hundred eleven billion, five hundred thirty-nine million, five hundred sixty-one thousand, thirteen".