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4112000047 is a prime number
BaseRepresentation
bin1111010100011000…
…0010010000101111
3101121120110020122001
43311012002100233
531410133000142
61520010233131
7203620265221
oct36506022057
911546406561
104112000047
111820131551
129691257a7
13506ba722c
142b018a411
15190eea5b7
hexf518242f

4112000047 has 2 divisors, whose sum is σ = 4112000048. Its totient is φ = 4112000046.

The previous prime is 4112000033. The next prime is 4112000147. The reversal of 4112000047 is 7400002114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4112000047 - 231 = 1964516399 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4111999988 and 4112000033.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4112000147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056000023 + 2056000024.

It is an arithmetic number, because the mean of its divisors is an integer number (2056000024).

Almost surely, 24112000047 is an apocalyptic number.

4112000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112000047 is an equidigital number, since it uses as much as digits as its factorization.

4112000047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 19.

The square root of 4112000047 is about 64124.8785339980. The cubic root of 4112000047 is about 1602.0806326352.

The spelling of 4112000047 in words is "four billion, one hundred twelve million, forty-seven", and thus it is an aban number.