41120104433 has 4 divisors (see below), whose sum is σ = 41995000320. Its totient is φ = 40245208548.

The previous prime is 41120104379. The next prime is 41120104463. The reversal of 41120104433 is 33440102114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41120104433 - 2²⁶ = 41052995569 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41120104399 and 41120104408.

It is not an unprimeable number, because it can be changed into a prime (41120104463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437447873 + ... + 437447966.

It is an arithmetic number, because the mean of its divisors is an integer number (10498750080).

Almost surely, 2^41120104433 is an apocalyptic number.

It is an amenable number.

41120104433 is a deficient number, since it is larger than the sum of its proper divisors (874895887).

41120104433 is an equidigital number, since it uses as much as digits as its factorization.

41120104433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 874895886.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 41120104433 its reverse (33440102114), we get a palindrome (74560206547).

The spelling of 41120104433 in words is "forty-one billion, one hundred twenty million, one hundred four thousand, four hundred thirty-three".