41120683877701 has 4 divisors (see below), whose sum is σ = 43284930397600. Its totient is φ = 38956437357804.

The previous prime is 41120683877699. The next prime is 41120683877719. The reversal of 41120683877701 is 10777838602114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41120683877701 - 2¹ = 41120683877699 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41120683877761) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1082123259921 + ... + 1082123259958.

It is an arithmetic number, because the mean of its divisors is an integer number (10821232599400).

Almost surely, 2^{41120683877701} is an apocalyptic number.

It is an amenable number.

41120683877701 is a deficient number, since it is larger than the sum of its proper divisors (2164246519899).

41120683877701 is a wasteful number, since it uses less digits than its factorization.

41120683877701 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2164246519898.

The product of its (nonzero) digits is 3161088, while the sum is 55.

The spelling of 41120683877701 in words is "forty-one trillion, one hundred twenty billion, six hundred eighty-three million, eight hundred seventy-seven thousand, seven hundred one".