4112113001 has 2 divisors, whose sum is σ = 4112113002. Its totient is φ = 4112113000.

The previous prime is 4112112997. The next prime is 4112113003. The reversal of 4112113001 is 1003112114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4111887376 + 225625 = 64124^2 + 475^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112113001 - 2² = 4112112997 is a prime.

Together with 4112113003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4112113003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056056500 + 2056056501.

It is an arithmetic number, because the mean of its divisors is an integer number (2056056501).

Almost surely, 2^4112113001 is an apocalyptic number.

It is an amenable number.

4112113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112113001 is an equidigital number, since it uses as much as digits as its factorization.

4112113001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 4112113001 is about 64125.7592625616. The cubic root of 4112113001 is about 1602.0953018762.

Adding to 4112113001 its reverse (1003112114), we get a palindrome (5115225115).

The spelling of 4112113001 in words is "four billion, one hundred twelve million, one hundred thirteen thousand, one".