4112124104121 has 16 divisors (see below), whose sum is σ = 6241326704640. Its totient is φ = 2383840059920.

The previous prime is 4112124104107. The next prime is 4112124104131. The reversal of 4112124104121 is 1214014212114.

It is not a de Polignac number, because 4112124104121 - 2⁷ = 4112124103993 is a prime.

It is a super-3 number, since 3×4112124104121³ (a number of 39 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4112124104091 and 4112124104100.

It is not an unprimeable number, because it can be changed into a prime (4112124104131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2708908401 + ... + 2708909918.

It is an arithmetic number, because the mean of its divisors is an integer number (390082919040).

Almost surely, 2^{4112124104121} is an apocalyptic number.

It is an amenable number.

4112124104121 is a deficient number, since it is larger than the sum of its proper divisors (2129202600519).

4112124104121 is a wasteful number, since it uses less digits than its factorization.

4112124104121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5417818356.

The product of its (nonzero) digits is 512, while the sum is 24.

Adding to 4112124104121 its reverse (1214014212114), we get a palindrome (5326138316235).

The spelling of 4112124104121 in words is "four trillion, one hundred twelve billion, one hundred twenty-four million, one hundred four thousand, one hundred twenty-one".