411213001 has 2 divisors, whose sum is σ = 411213002. Its totient is φ = 411213000.

The previous prime is 411212993. The next prime is 411213041. The reversal of 411213001 is 100312114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 367718976 + 43494025 = 19176^2 + 6595^2 .

It is a cyclic number.

It is not a de Polignac number, because 411213001 - 2³ = 411212993 is a prime.

It is a super-2 number, since 2×411213001² = 338192264382852002, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (411213041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205606500 + 205606501.

It is an arithmetic number, because the mean of its divisors is an integer number (205606501).

Almost surely, 2^411213001 is an apocalyptic number.

It is an amenable number.

411213001 is a deficient number, since it is larger than the sum of its proper divisors (1).

411213001 is an equidigital number, since it uses as much as digits as its factorization.

411213001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 411213001 is about 20278.3875345157. The cubic root of 411213001 is about 743.6277916476.

Adding to 411213001 its reverse (100312114), we get a palindrome (511525115).

The spelling of 411213001 in words is "four hundred eleven million, two hundred thirteen thousand, one".