Base | Representation |
---|---|
bin | 1011111101111100011… |
… | …01111000001010110110 |
3 | 1110022102011012001112101 |
4 | 11332332031320022312 |
5 | 23214131034431402 |
6 | 512524142012314 |
7 | 41465150355223 |
oct | 5767615701266 |
9 | 1408364161471 |
10 | 411213202102 |
11 | 14943815007a |
12 | 6784257709a |
13 | 2ca14793181 |
14 | 15c8d4d094a |
15 | aa6b04db87 |
hex | 5fbe3782b6 |
411213202102 has 16 divisors (see below), whose sum is σ = 657332485632. Its totient is φ = 192482774440.
The previous prime is 411213202097. The next prime is 411213202123. The reversal of 411213202102 is 201202312114.
It is a self number, because there is not a number n which added to its sum of digits gives 411213202102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 95098024 + ... + 95102347.
It is an arithmetic number, because the mean of its divisors is an integer number (41083280352).
Almost surely, 2411213202102 is an apocalyptic number.
411213202102 is a deficient number, since it is larger than the sum of its proper divisors (246119283530).
411213202102 is a wasteful number, since it uses less digits than its factorization.
411213202102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190200443.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 411213202102 its reverse (201202312114), we get a palindrome (612415514216).
The spelling of 411213202102 in words is "four hundred eleven billion, two hundred thirteen million, two hundred two thousand, one hundred two".
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