41121403351 has 4 divisors (see below), whose sum is σ = 46995889552. Its totient is φ = 35246917152.

The previous prime is 41121403327. The next prime is 41121403403. The reversal of 41121403351 is 15330412114.

41121403351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41121403351 - 2⁵ = 41121403319 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41121403451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2937243090 + ... + 2937243103.

It is an arithmetic number, because the mean of its divisors is an integer number (11748972388).

Almost surely, 2^41121403351 is an apocalyptic number.

41121403351 is a deficient number, since it is larger than the sum of its proper divisors (5874486201).

41121403351 is an equidigital number, since it uses as much as digits as its factorization.

41121403351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5874486200.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41121403351 its reverse (15330412114), we get a palindrome (56451815465).

The spelling of 41121403351 in words is "forty-one billion, one hundred twenty-one million, four hundred three thousand, three hundred fifty-one".