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41122132400 = 2452232316269
BaseRepresentation
bin100110010011000100…
…011111000110110000
310221010212112202202202
4212103010133012300
51133204231214100
630520302002332
72654021233556
oct462304370660
9127125482682
1041122132400
111649240a798
127b778763a8
133b546b212b
141dc162bbd6
15110a2907d5
hex99311f1b0

41122132400 has 180 divisors, whose sum is σ = 106626717120. Its totient is φ = 15223718400.

The previous prime is 41122132393. The next prime is 41122132511. The reversal of 41122132400 is 423122114.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 6556466 + ... + 6562734.

Almost surely, 241122132400 is an apocalyptic number.

41122132400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 41122132400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (53313358560).

41122132400 is an abundant number, since it is smaller than the sum of its proper divisors (65504584720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41122132400 is a wasteful number, since it uses less digits than its factorization.

41122132400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6364 (or 6330 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 41122132400 its reverse (423122114), we get a palindrome (41545254514).

The spelling of 41122132400 in words is "forty-one billion, one hundred twenty-two million, one hundred thirty-two thousand, four hundred".