4112222311233 has 6 divisors (see below), whose sum is σ = 5939876671794. Its totient is φ = 2741481540816.

The previous prime is 4112222311159. The next prime is 4112222311271. The reversal of 4112222311233 is 3321132222114.

4112222311233 is a `hidden beast` number, since 4 + 112 + 2 + 2 + 2 + 311 + 233 = 666.

It can be written as a sum of positive squares in only one way, i.e., 2953094460849 + 1159127850384 = 1718457^2 + 1076628^2 .

It is a de Polignac number, because none of the positive numbers 2^k-4112222311233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4112222311197 and 4112222311206.

It is not an unprimeable number, because it can be changed into a prime (4112222311033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 228456795060 + ... + 228456795077.

It is an arithmetic number, because the mean of its divisors is an integer number (989979445299).

Almost surely, 2^{4112222311233} is an apocalyptic number.

It is an amenable number.

4112222311233 is a deficient number, since it is larger than the sum of its proper divisors (1827654360561).

4112222311233 is a wasteful number, since it uses less digits than its factorization.

4112222311233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 456913590143 (or 456913590140 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 4112222311233 its reverse (3321132222114), we get a palindrome (7433354533347).

The spelling of 4112222311233 in words is "four trillion, one hundred twelve billion, two hundred twenty-two million, three hundred eleven thousand, two hundred thirty-three".