411230413211113 has 4 divisors (see below), whose sum is σ = 412747868610688. Its totient is φ = 409712957811540.

The previous prime is 411230413211087. The next prime is 411230413211143. The reversal of 411230413211113 is 311112314032114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411230413211113 - 2⁵ = 411230413211081 is a prime.

It is a super-2 number, since 2×411230413211113² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (411230413211143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 758727699381 + ... + 758727699922.

It is an arithmetic number, because the mean of its divisors is an integer number (103186967152672).

Almost surely, 2^{411230413211113} is an apocalyptic number.

It is an amenable number.

411230413211113 is a deficient number, since it is larger than the sum of its proper divisors (1517455399575).

411230413211113 is a wasteful number, since it uses less digits than its factorization.

411230413211113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1517455399574.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 411230413211113 its reverse (311112314032114), we get a palindrome (722342727243227).

The spelling of 411230413211113 in words is "four hundred eleven trillion, two hundred thirty billion, four hundred thirteen million, two hundred eleven thousand, one hundred thirteen".