Base | Representation |
---|---|
bin | 100110010011001000… |
… | …111101011100100011 |
3 | 10221010221202100121200 |
4 | 212103020331130203 |
5 | 1133210031232001 |
6 | 30520343052243 |
7 | 2654034220140 |
oct | 462310753443 |
9 | 127127670550 |
10 | 41123305251 |
11 | 16493040996 |
12 | 7b78141083 |
13 | 3b54a02c22 |
14 | 1dc18553c7 |
15 | 110a423086 |
hex | 99323d723 |
41123305251 has 12 divisors (see below), whose sum is σ = 67886091312. Its totient is φ = 23499031536.
The previous prime is 41123305243. The next prime is 41123305309. The reversal of 41123305251 is 15250332114.
41123305251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 41123305251 - 23 = 41123305243 is a prime.
It is a super-2 number, since 2×411233052512 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (41123105251) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 326375376 + ... + 326375501.
It is an arithmetic number, because the mean of its divisors is an integer number (5657174276).
Almost surely, 241123305251 is an apocalyptic number.
41123305251 is a deficient number, since it is larger than the sum of its proper divisors (26762786061).
41123305251 is a wasteful number, since it uses less digits than its factorization.
41123305251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652750890 (or 652750887 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 41123305251 its reverse (15250332114), we get a palindrome (56373637365).
The spelling of 41123305251 in words is "forty-one billion, one hundred twenty-three million, three hundred five thousand, two hundred fifty-one".
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