Base | Representation |
---|---|
bin | 111011110101111010001… |
… | …011001001010101001111 |
3 | 112120010122120212221022001 |
4 | 323311322023021111033 |
5 | 1014334024330210211 |
6 | 12425102505333131 |
7 | 603051312350422 |
oct | 73657213112517 |
9 | 15503576787261 |
10 | 4112333444431 |
11 | 1346038026053 |
12 | 564bb81971a7 |
13 | 23aa3987a494 |
14 | 1030763b99b9 |
15 | 71e87d7dac1 |
hex | 3bd7a2c954f |
4112333444431 has 4 divisors (see below), whose sum is σ = 4112356002552. Its totient is φ = 4112310886312.
The previous prime is 4112333444357. The next prime is 4112333444467. The reversal of 4112333444431 is 1344443332114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4112333444431 is a prime.
It is a super-2 number, since 2×41123334444312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4112333444731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11003365 + ... + 11370958.
It is an arithmetic number, because the mean of its divisors is an integer number (1028089000638).
Almost surely, 24112333444431 is an apocalyptic number.
4112333444431 is a deficient number, since it is larger than the sum of its proper divisors (22558121).
4112333444431 is a wasteful number, since it uses less digits than its factorization.
4112333444431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22558120.
The product of its digits is 165888, while the sum is 37.
Adding to 4112333444431 its reverse (1344443332114), we get a palindrome (5456776776545).
The spelling of 4112333444431 in words is "four trillion, one hundred twelve billion, three hundred thirty-three million, four hundred forty-four thousand, four hundred thirty-one".
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