411240110312121 has 4 divisors (see below), whose sum is σ = 548320147082832. Its totient is φ = 274160073541412.

The previous prime is 411240110312081. The next prime is 411240110312191. The reversal of 411240110312121 is 121213011042114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411240110312121 - 2¹⁴ = 411240110295737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 411240110312091 and 411240110312100.

It is not an unprimeable number, because it can be changed into a prime (411240110312191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68540018385351 + ... + 68540018385356.

It is an arithmetic number, because the mean of its divisors is an integer number (137080036770708).

Almost surely, 2^{411240110312121} is an apocalyptic number.

It is an amenable number.

411240110312121 is a deficient number, since it is larger than the sum of its proper divisors (137080036770711).

411240110312121 is a wasteful number, since it uses less digits than its factorization.

411240110312121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137080036770710.

The product of its (nonzero) digits is 384, while the sum is 24.

Adding to 411240110312121 its reverse (121213011042114), we get a palindrome (532453121354235).

The spelling of 411240110312121 in words is "four hundred eleven trillion, two hundred forty billion, one hundred ten million, three hundred twelve thousand, one hundred twenty-one".