411243424342113 has 8 divisors (see below), whose sum is σ = 598172253588576. Its totient is φ = 249238438995200.

The previous prime is 411243424342087. The next prime is 411243424342129. The reversal of 411243424342113 is 311243424342114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 411243424342113 - 2¹⁰ = 411243424341089 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (411243424342133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6230960974848 + ... + 6230960974913.

It is an arithmetic number, because the mean of its divisors is an integer number (74771531698572).

Almost surely, 2^{411243424342113} is an apocalyptic number.

It is an amenable number.

411243424342113 is a deficient number, since it is larger than the sum of its proper divisors (186928829246463).

411243424342113 is a wasteful number, since it uses less digits than its factorization.

411243424342113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12461921949775.

The product of its digits is 221184, while the sum is 39.

Adding to 411243424342113 its reverse (311243424342114), we get a palindrome (722486848684227).

Subtracting from 411243424342113 its reverse (311243424342114), we obtain a palindrome (99999999999999).

The spelling of 411243424342113 in words is "four hundred eleven trillion, two hundred forty-three billion, four hundred twenty-four million, three hundred forty-two thousand, one hundred thirteen".