Base | Representation |
---|---|
bin | 101110110000001100001001… |
… | …0001110010110000001100011 |
3 | 1222221002111011022202121201212 |
4 | 1131200120102032112001203 |
5 | 412400303013112421430 |
6 | 4014350342051020335 |
7 | 152423233265653331 |
oct | 13540302216260143 |
9 | 1887074138677655 |
10 | 411243424342115 |
11 | 10a0423a1a46752 |
12 | 3a15989289a6ab |
13 | 1486111c60cc61 |
14 | 737a406174b51 |
15 | 32825ba1a8b95 |
hex | 1760612396063 |
411243424342115 has 16 divisors (see below), whose sum is σ = 518128616990880. Its totient is φ = 312909047109120.
The previous prime is 411243424342087. The next prime is 411243424342129. The reversal of 411243424342115 is 511243424342114.
It is a happy number.
It is not a de Polignac number, because 411243424342115 - 238 = 410968546435171 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21165374966 + ... + 21165394395.
It is an arithmetic number, because the mean of its divisors is an integer number (32383038561930).
Almost surely, 2411243424342115 is an apocalyptic number.
411243424342115 is a deficient number, since it is larger than the sum of its proper divisors (106885192648765).
411243424342115 is a wasteful number, since it uses less digits than its factorization.
411243424342115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42330769462.
The product of its digits is 368640, while the sum is 41.
Adding to 411243424342115 its reverse (511243424342114), we get a palindrome (922486848684229).
Subtracting 411243424342115 from its reverse (511243424342114), we obtain a palindrome (99999999999999).
The spelling of 411243424342115 in words is "four hundred eleven trillion, two hundred forty-three billion, four hundred twenty-four million, three hundred forty-two thousand, one hundred fifteen".
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