Base | Representation |
---|---|
bin | 100110010011001111… |
… | …111001011000101111 |
3 | 10221011002011201222002 |
4 | 212103033321120233 |
5 | 1133211012424011 |
6 | 30520450042515 |
7 | 2654055532424 |
oct | 462317713057 |
9 | 127132151862 |
10 | 41125123631 |
11 | 16494073089 |
12 | 7b7887943b |
13 | 3b551bb7a7 |
14 | 1dc1ba9d4b |
15 | 110a681c3b |
hex | 9933f962f |
41125123631 has 2 divisors, whose sum is σ = 41125123632. Its totient is φ = 41125123630.
The previous prime is 41125123547. The next prime is 41125123643. The reversal of 41125123631 is 13632152114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41125123631 - 218 = 41124861487 is a prime.
It is a super-2 number, since 2×411251236312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41125123594 and 41125123603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41125129631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20562561815 + 20562561816.
It is an arithmetic number, because the mean of its divisors is an integer number (20562561816).
Almost surely, 241125123631 is an apocalyptic number.
41125123631 is a deficient number, since it is larger than the sum of its proper divisors (1).
41125123631 is an equidigital number, since it uses as much as digits as its factorization.
41125123631 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320, while the sum is 29.
Adding to 41125123631 its reverse (13632152114), we get a palindrome (54757275745).
The spelling of 41125123631 in words is "forty-one billion, one hundred twenty-five million, one hundred twenty-three thousand, six hundred thirty-one".
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