Base | Representation |
---|---|
bin | 111011110110100010100… |
… | …101000011000011110011 |
3 | 112120012101211102202001021 |
4 | 323312202211003003303 |
5 | 1014341421344314443 |
6 | 12425254042520311 |
7 | 603104153256223 |
oct | 73664245030363 |
9 | 15505354382037 |
10 | 4113011323123 |
11 | 134635573637a |
12 | 565167206097 |
13 | 23ab17142a31 |
14 | 1030dc436083 |
15 | 71ec76319ed |
hex | 3bda29430f3 |
4113011323123 has 2 divisors, whose sum is σ = 4113011323124. Its totient is φ = 4113011323122.
The previous prime is 4113011323121. The next prime is 4113011323247. The reversal of 4113011323123 is 3213231103114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4113011323123 - 21 = 4113011323121 is a prime.
It is a super-2 number, since 2×41130113231232 (a number of 26 digits) contains 22 as substring.
Together with 4113011323121, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4113011323121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056505661561 + 2056505661562.
It is an arithmetic number, because the mean of its divisors is an integer number (2056505661562).
Almost surely, 24113011323123 is an apocalyptic number.
4113011323123 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113011323123 is an equidigital number, since it uses as much as digits as its factorization.
4113011323123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 4113011323123 its reverse (3213231103114), we get a palindrome (7326242426237).
The spelling of 4113011323123 in words is "four trillion, one hundred thirteen billion, eleven million, three hundred twenty-three thousand, one hundred twenty-three".
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