Base | Representation |
---|---|
bin | 111011110110100010110… |
… | …000001000110011010111 |
3 | 112120012102000220102211221 |
4 | 323312202300020303113 |
5 | 1014341423120331411 |
6 | 12425254225111211 |
7 | 603104220054604 |
oct | 73664260106327 |
9 | 15505360812757 |
10 | 4113014230231 |
11 | 1346357341545 |
12 | 565168188507 |
13 | 23ab1792000a |
14 | 1030dc9916ab |
15 | 71ec7a08071 |
hex | 3bda2c08cd7 |
4113014230231 has 32 divisors (see below), whose sum is σ = 4541521727232. Its totient is φ = 3708510220800.
The previous prime is 4113014230219. The next prime is 4113014230253. The reversal of 4113014230231 is 1320324103114.
It is a cyclic number.
It is not a de Polignac number, because 4113014230231 - 233 = 4104424295639 is a prime.
It is a super-2 number, since 2×41130142302312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4113014230196 and 4113014230205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113014210231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95516656 + ... + 95559706.
It is an arithmetic number, because the mean of its divisors is an integer number (141922553976).
Almost surely, 24113014230231 is an apocalyptic number.
4113014230231 is a deficient number, since it is larger than the sum of its proper divisors (428507497001).
4113014230231 is a wasteful number, since it uses less digits than its factorization.
4113014230231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45439.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4113014230231 its reverse (1320324103114), we get a palindrome (5433338333345).
The spelling of 4113014230231 in words is "four trillion, one hundred thirteen billion, fourteen million, two hundred thirty thousand, two hundred thirty-one".
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