Base | Representation |
---|---|
bin | 111011110110100011010… |
… | …110010100111011010011 |
3 | 112120012102201202001112121 |
4 | 323312203112110323103 |
5 | 1014341433201210423 |
6 | 12425255223435111 |
7 | 603104401131562 |
oct | 73664326247323 |
9 | 15505381661477 |
10 | 4113024241363 |
11 | 1346361a5a004 |
12 | 56516b5b5a97 |
13 | 23ab19a1696b |
14 | 103100039bd9 |
15 | 71ec883445d |
hex | 3bda3594ed3 |
4113024241363 has 2 divisors, whose sum is σ = 4113024241364. Its totient is φ = 4113024241362.
The previous prime is 4113024241331. The next prime is 4113024241397. The reversal of 4113024241363 is 3631424203114.
It is an a-pointer prime, because the next prime (4113024241397) can be obtained adding 4113024241363 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4113024241363 - 25 = 4113024241331 is a prime.
It is not a weakly prime, because it can be changed into another prime (4113024242363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056512120681 + 2056512120682.
It is an arithmetic number, because the mean of its divisors is an integer number (2056512120682).
Almost surely, 24113024241363 is an apocalyptic number.
4113024241363 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113024241363 is an equidigital number, since it uses as much as digits as its factorization.
4113024241363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 4113024241363 its reverse (3631424203114), we get a palindrome (7744448444477).
The spelling of 4113024241363 in words is "four trillion, one hundred thirteen billion, twenty-four million, two hundred forty-one thousand, three hundred sixty-three".
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