Base | Representation |
---|---|
bin | 100110010011100011… |
… | …101110111000001111 |
3 | 10221011102221220210202 |
4 | 212103203232320033 |
5 | 1133213330322341 |
6 | 30521153324115 |
7 | 2654150660336 |
oct | 462343567017 |
9 | 127142856722 |
10 | 41130323471 |
11 | 16496aa4876 |
12 | 7b7a56663b |
13 | 3b562bc513 |
14 | 1dc2760d1d |
15 | 110ad5c79b |
hex | 9938eee0f |
41130323471 has 2 divisors, whose sum is σ = 41130323472. Its totient is φ = 41130323470.
The previous prime is 41130323401. The next prime is 41130323477. The reversal of 41130323471 is 17432303114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41130323471 - 222 = 41126129167 is a prime.
It is a super-3 number, since 3×411303234713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41130323477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565161735 + 20565161736.
It is an arithmetic number, because the mean of its divisors is an integer number (20565161736).
Almost surely, 241130323471 is an apocalyptic number.
41130323471 is a deficient number, since it is larger than the sum of its proper divisors (1).
41130323471 is an equidigital number, since it uses as much as digits as its factorization.
41130323471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 41130323471 its reverse (17432303114), we get a palindrome (58562626585).
The spelling of 41130323471 in words is "forty-one billion, one hundred thirty million, three hundred twenty-three thousand, four hundred seventy-one".
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