Base | Representation |
---|---|
bin | 111011110110100100010… |
… | …011101010111100000111 |
3 | 112120012110212000001110021 |
4 | 323312210103222330013 |
5 | 1014342001310303221 |
6 | 12425301000240011 |
7 | 603104654616034 |
oct | 73664423527407 |
9 | 15505425001407 |
10 | 4113040322311 |
11 | 1346370042948 |
12 | 565174a70007 |
13 | 23ab2015730b |
14 | 10310222438b |
15 | 71ec9e5e041 |
hex | 3bda44eaf07 |
4113040322311 has 4 divisors (see below), whose sum is σ = 4113505134000. Its totient is φ = 4112575510624.
The previous prime is 4113040322257. The next prime is 4113040322351. The reversal of 4113040322311 is 1132230403114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113040322311 - 215 = 4113040289543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113040322351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232392571 + ... + 232410268.
It is an arithmetic number, because the mean of its divisors is an integer number (1028376283500).
Almost surely, 24113040322311 is an apocalyptic number.
4113040322311 is a deficient number, since it is larger than the sum of its proper divisors (464811689).
4113040322311 is an equidigital number, since it uses as much as digits as its factorization.
4113040322311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 464811688.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4113040322311 its reverse (1132230403114), we get a palindrome (5245270725425).
The spelling of 4113040322311 in words is "four trillion, one hundred thirteen billion, forty million, three hundred twenty-two thousand, three hundred eleven".
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