Base | Representation |
---|---|
bin | 111011110110100111111… |
… | …100000001110000111101 |
3 | 112120012122002121122111121 |
4 | 323312213330001300331 |
5 | 1014342112403430323 |
6 | 12425311013550541 |
7 | 603106324425610 |
oct | 73664774016075 |
9 | 15505562548447 |
10 | 4113101233213 |
11 | 13463a1466135 |
12 | 565191345451 |
13 | 23ab2c962a7b |
14 | 10310a35c177 |
15 | 71ed0491a5d |
hex | 3bda7f01c3d |
4113101233213 has 8 divisors (see below), whose sum is σ = 4702565164928. Its totient is φ = 3524106811824.
The previous prime is 4113101233151. The next prime is 4113101233229. The reversal of 4113101233213 is 3123321013114.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4113101233213 - 213 = 4113101225021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113191233213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117358806 + ... + 117393847.
It is an arithmetic number, because the mean of its divisors is an integer number (587820645616).
Almost surely, 24113101233213 is an apocalyptic number.
It is an amenable number.
4113101233213 is a deficient number, since it is larger than the sum of its proper divisors (589463931715).
4113101233213 is a wasteful number, since it uses less digits than its factorization.
4113101233213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 234755163.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 4113101233213 its reverse (3123321013114), we get a palindrome (7236422246327).
The spelling of 4113101233213 in words is "four trillion, one hundred thirteen billion, one hundred one million, two hundred thirty-three thousand, two hundred thirteen".
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